Question

A father is 30 years older than his son.In 12 years the man will be 3 times as old as his son.Find their present ages.

(please I want the answer is the process)

Answer 1

Let the age of the father be 'x'
Let the age of his son be 'y'
Therefore , x=30+y
12+x=3(12+y)
=12+(30+y)=36+3y
=y+42=36+3y
=y+6=3y
=2y=6
Therefore , y=3
Therefore, the son's present age would be 3 yrs
Father's age = 30 + y
=30+3=33
Therefore, father's present age is 33.
Answer: father's present age is 33 and son's present age js 3 yrs.

Answer 2

Let the present age of the father be x and the son be y years.

Given that A father is 30 years older than his son.

x = y + 30.


After 12 years:

Age of father = x + 12

Age of son = y + 12.


Given that In 12 years the man will be 3 times as old as his son.

x + 12 = 3(y + 12)

y + 30 + 12  = 3y + 36

y + 42 = 3y + 36

-2y = -6

y = 3.


Substitute y = 3 in (1), we get

x = y + 30

x = 3 + 30

x = 33..


Therefore the age of father = 33 years and the age of son = 3 years.


Verification:

x = y + 30

33 = 3 + 30

33 = 33.



Hope this helps!