Question

a father is 30 years older than his son. In 12 years the man will be 3 times as old as his son. Find their present ages

Answer 1

Answer:

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Answer 2

Answer:

father = 30 + x

son = x

12 year before ages,=

father = 3x

son = x

30+x+12/x+12=3x/x

42+x/x+12=3x / x

42x +x^2 = 3x^2 + 12x

42x-12x = 3x^2 - x^2

30x = 2x^2

x = 15

father = 45

son = 15