Question

A father is 30 years older than his son. In 6 years, the father will be thrice as old as

his son. Find the age of father.​

Answer 1

Step-by-step explanation:

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Let the current age of the son be [math]x[/math] years old.

Current age of father = [math]x + 30[/math]

In 12 years:

Final age of father = [math](x + 30) + 12 = x+42[/math]

Final age of son = [math]x + 12[/math]

Now since we know that the final age of the father is three times the final age of the son:

[math]x + 42 = 3(x+12)[/math]

[math]x + 42 = 3x + 36[/math]

[math]2x = 42 - 36 = 6[/math]

[math]x = 3[/math]

[math]x + 30 = 3 + 30 = 33[/math]

Therefore, the current age of the son is 3 years old and the current age of the father is 33 years old.

Answer 2

Step-by-step explanation:

Let the age of son be x years

age of father =x+30 year

After 6 year age of son=x+6 years

After 6 year age of father=x+30+6 years =x+36 years

3(x+6) = x+36

3x+18 =x+36

3x-x =36-18

2x =18

x= 18÷2

x=9

Age of father = x+30 years

9+30

=39 years

Hence age of father is 39 years.