Question

A father is 30 years older than his son. in 6 years time, he will be twice as old as his son. what are their present ages?

Answer 1

Answer:

let the required present ages be x

1. 30*by 2,6*by x
2. =60,
3. 6*x=30
4. 6x=30
5. x=30/6=5
6. so, x=5,then
7. 6*x=5
8. x=6*5=30
9. ans=the age of father is 60 years and the age of the son is 30 years with a difference of 30 years.