Question

a father is 4 times as old as his son. in 20 years father will be twice as old as his son. Find present age​

Answer 1

Let the present age of the son be x,

Father's present age= 4x

After 20 years ,

Son's age = x+20

Father's age= 4x+20

Now given that after 20 years , father will be 2twice his son's age. so,

4x+20= 2(x+20)

4x+20=2x+40

4x-2x=40-20

2x= 20

x= 20/2

x= 10 years

So son's present age is 10 years .

Father's present age= 4x= 4*10=40years

Therefore Father's present age is 40 years and son's present age is 10years.

$MILE ¶LZ!!

Answer 2

Father age is 40 I did it in my own note