A father is 7 time as old as his son. Two years
ago the father was 13 times as old as his
son. What are there present ago?
Answers
Answered by
1
Answer:
2 years ago the father was 13 times as old as his son, how old are they now. DAD=7X WHEN THE SON'S AGE IS X NOW. X=4 THE AGE OF THE SON NOW. THUS THE DAD=7*4=28 YEARS OLD NOW
Answered by
4
Answer:
The present ages of son and father are 4 years and 28 years respectively.
Step-by-step-explanation:
Let the present age of son be x years.
And the present age of father be 7x years.
Now,
Age of son two years ago = ( x - 2 ) years
Age of father two years ago = ( 7x - 2 ) years
From the given condition,
( 7x - 2 ) = 13 ( x - 2 )
⇒ 7x - 2 = 13x - 26
⇒ - 2 + 26 = 13x - 7x
⇒ 24 = 6x
⇒ x = 24 ÷ 6
⇒ x = 4
∴ Present age of son = 4 years
Now,
Present age of father = 7x
⇒ Present age of father = 7 * 4
⇒ Present age of father = 28 years
∴ The present ages of son and father are 4 years and 28 years respectively.
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