Question

a father is 7 times as old as his son 2 years ago the father was 13 times old as his son how old they now

Answer 1

Hi ,

At present
__________

Age of the son = x years

Father's age = 7x years

2 years ago
_________

Son's age = ( x - 2 ) years

Father's age = ( 7x - 2 ) years

According to the problem given,

7x - 2 = 13 ( x - 2 )

7x - 2 = 13x - 26

7x - 13x = -26 + 2

-6x = -24

x = ( -24 ) / ( -6 )

x = 4

Therefore ,

At present ,

Son age = x = 4years

Father's age = 7x = 7 × 4 = 28years

I hope this helps you.

:)

Answer 2

let
the age of son be X
and his father's age be 7X

2 years ago
son age =X-2
father's age =7X-2

according to the above equation
7X-2=13(X-2)
7X-2=13x-26
7x-13x= -26+2
-6x =-24
x= 4
now we get
son's age= 4 years
and father's age=7x=7×4=28 years


hope it is helpful