A FATHER IS 7 TIMES AS OLD AS HIS SON . THREE YEARS AGO THE FATHER WAS THIRTEEN
TIMES AS OLD AS HIS SON. WHAT ARE THERE PRESENT AGES.?
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Let the present age of the son be x and that to of his father which is 7 times =7x
Then, 2 years ago their ages :
(x-2) of son
(7x-2) of father
Given, 13(x−2)=7x−2
Then,
13x−26=7x−2
=13x−7x=26−2
6x=24
or x=4 and that of his father = 28 years
age of son=x=4years
age of father=7x=28years//
28 IS THE ANSWER
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