Question

A father is 7 times as old as his son. Two years ago, the father was 13 times as old as
his son. How old are they now?
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Answer 1

Answer:

Refer the attachment given above

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Answer 2

Answer:

LET THE AGE OF SON BE x YEARS.

AGE OF FATHER = 7x YEARS

TWO YEARS AGO,

AGE OF SON = x-2 YEARS

AGE OF FATHER = 7x-2 YEARS.

IT IS ALSO GIVEN TAHT TWO YEARS AGO AGE OF FATHER WAS 13 TIMES OF AGE OF SON . SO,

7x-2 = 13(x-2)

7x-2 = 13x-26

6x = 24

x = 4 YEARS

AT PRESENT,

AGE OF FATHER IS 28 YEARS.

AGE OF SON IS 4 YEARS.