Question

a father is 7 times as old as his son Twp years ago, the father was 13 times as old as his son. how old are they now?​

Answer 1

Step-by-step explanation:

Let the son's age be 'x'

Hence the father's age is 7x

two years ago

Son's age=x-2

Father's age=7x-2 or 13(x-2)

7x-2 = 13(x-2)

7x-2 = 13x -26

7x-13x = -26+2

-6x = -24

x=-24/-6

=4

Hence son's age is 4.

Father's age is 7×4=28yrs.

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