Question

a father is older than his first son by 30yr.The first son is older than the second son by 10yr.If the sum of their ages is 95yr Find the age of the father?

Answer 1

Hello !!


Let the present age of second son be X years.


Age of first son = ( X + 10 )



Age of father = ( X + 10 + 30 )



According to the question,


X+ X+ 10 + X + 40 = 95


3X + 50 = 95



3X = 95-50



3X = 45


X = 45/3 = 15 years.



Age of second son = ( X ) = 15 years.



Age of first son = ( X + 10 ) = 15+10 = 25 years.


And,


Age of father = X+ 40 = 15+40 = 55 years.

Answer 2

Let age of 2nd son be x yrs

age of 1st son = ( x + 10 ) yrs

age of father = x + 10 + 30 = ( x + 40 ) yrs

now,

x + x + 10 + x + 40 = 95

3x + 50 = 95

3x = 45

x = 15

father's age = 15 + 40 = 55 yrs

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