a father is three times as old as his son after 12 years his age will be twice as that of his son then find their present Ages by elimination method
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Answer:
son age =x
father s age= 3x
after 12 years sons age=x+12
fathers age=2(x+12)=2x+24 or 3x+12
2x+24=3x+12
=24-12=3x-2x
=12=x
present age of son=12
present age of father=12*3=36
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Answer:
Father's Present age =36
Son's Present age = 12
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