a father is three times as old as his son after 15 years he will be twice as old as his son what are their present ages
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Answered by
16
Let the present age of son be a
Present age of father = 3a
According to question,
3a + 15 = 2 ( a + 15)
=> 3a + 15 = 2a + 30
=> a = 15
Son's present age = 15 years
Father's present age = 45 years
Present age of father = 3a
According to question,
3a + 15 = 2 ( a + 15)
=> 3a + 15 = 2a + 30
=> a = 15
Son's present age = 15 years
Father's present age = 45 years
Answered by
5
let present age of son be c year's.
father age = 3c year's.
according to question
2 ( c + 15 ) = 3c + 15
2c + 30 = 3c + 15
c = 15 years.
present age of son = 15 years.
present age of Father = 45 years.
father age = 3c year's.
according to question
2 ( c + 15 ) = 3c + 15
2c + 30 = 3c + 15
c = 15 years.
present age of son = 15 years.
present age of Father = 45 years.
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