Question

the displacement 'x' (in meter) of particle of mass 'm' (in kg) moving in one dimension under the action of a force, is related to time 't' (in second) by t=√x+3. the displacement of the particle when it's velocity is zero, will be


a) 2m

b) 4m

c) 0(zero) m

d) 6m

Answer 1

Answer:0 m.

Explanation:

Since v= 0 and x= ( t-3) ²

X= t2-6t+9

dx/dt= 2t-6

T=3 sec.

X=3×3-6×3+9

X=0. Answer

Hope it will satisfied you.

Answer 2

Answer:

So the correct answer is "zero"

Explanation:

Displacement is described because the extrade in function of an item. It is a vector amount and has a path and magnitude. It is represented as an arrow that factors from the beginning function to the very last function. For example- If an item movements from A function to B, then the item's function changes.

Velocity is basically a vector amount. It is the price of extrade of distance. It is the price of extrade of displacement. Speed of an item transferring can by no means be negative. The pace of a transferring item may be zero Velocity (v) is a vector amount that measures displacement (or extrade in function, Δs) over the extrade in time (Δt), represented with the aid of using the equation v = Δs/Δt.

Given t =$\sqrt{x}$+3

          $\sqrt{x}$=3-t

squaring both sides we get

x=(t-3)²

velocity v = dx/dt  

                =d/dt (t-3)²=2(t-3)

velocity of particle becomes zero when

2(t-3)=0

t=3s

at t = 3s

x=(3-3)²

x=0

#SPJ3