a father is three times as old as his son after 5 years his age will be 2 and half times that of his son represent algebraically
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Answer:
age of son = x
age of father = y = 3x
after 5 years
y + 5 = 2.5(x + 5)
3x + 5 = 2.5x + 12.5
.5x = 7.5
x = 15
age of father = 45
age of son = 15
x + y = 75
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