what extra force should an engine of a car develop such that its velocity changes from 5m/s to 25m/s over a distance of 10m ,when the mass of the car is 900kg?
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Answer:
Explanation:
=> It is given that,
Initial speed, u= 5 m /s ;
final speed, v = 25 m /s ;
distance, S = 10 m
Force, F = ?
=> Lets find acceleration first by using below formula to get extra force:
v² = u² + 2*a*S
25 * 25 = (5*5)+2*a*10
a = 30 m/s²
=> Force:
F = m*a
F = 900 * 30 = 27,000 N
Thus, Extra force developed by car should be 27,000 N.
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