Question

A father is three times as old as his son. In 12 years time, he will be twice as old as his son. Find the present ages of father and the son.

Answer 1

Answer:

Son = 12

Fayher = 36

Step-by-step explanation:

Let , the age of son = x

the age of father = 3x

Afrer 12 years ,

Age of son = x + 12

Age of father = 3x + 12

Also,

Age of son = x + 12

Age of father = 2 ( x + 12 )

3x + 12 = 2 ( x + 12 )

3x + 12 = 2x + 24

3x - 2x = 24 - 12

x = 12

Thus ,

Age of son = x = 12

Age of father = 3x = 3 × 12 = 36 .

Answer 2

$\huge\mathbb{\underline{SOLUTION:-}}$

• Let son's age = x
• Two years ago son's age= x-2.
• His Father's age at that time = 3(x-2).
• Present age of Father = 3x-6+2=3x-4
• Two years hence father's age = 3x-4+2=3x-2.
• Two years hence son's age = x+2.

Given :-

5×(x+2)=2*(3x-2)

5x + 10= 6x - 4

10+4=6x-5x

14=x

SON'S PRESENT AGE : 14 years.

FATHER'S PTESENT AGE: 38 years.

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