A father is three times as old as his son. In 12 years time, he will be twice as old as his son. Di d the present age of father and son
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let his son age x so
age of father in present is 3x
age of son after 12 years is x+12
age of father after 12 years is 3x+12
ATO,
2(x+12) =3x +12
solve it u will get answer
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Let , present age of Father and Son Be X and Y
Present Age Of father = 3 × present Age of His son
X = 3Y --------- 1
After 12 years
Age of father = 2 × Age of his son
(X + 12) = 2 × (Y + 12)
X + 12 = 2Y + 24
X - 2Y = 12 --------- 2
Put The Value Of X = 3Y in equation 2
3Y - 2Y = 12
➡Y = 12
Put The Value Of Y = 12 In equation 1
X = 3 × 12
➡X = 36
Hence , Present Age of Father is 36 and present age of son is 12
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