Question

A father is three times old as his son.5 years ago fathers age was 4 times his sons ages.Find their present ages.

Answer 1

Step-by-step explanation:

let, the present age of the son be x

then, the present age of the father=3x

after 5 years,

their ages be x-5 and 3x-5 respectively

a/q

3x-5=4(x-5)

3x-5=4x-20

-5+20=4x-3x

15=x

x=15

therefore,

the present age of father=3x-5=45-5=40years

the present age of son=x-5=15-5=10years

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