Question

A father is twice as old as his son 20 years ago the age of the father was 12 times the age of son.​

Answer 1

Answer:

Let the age of the son be = x

Let the age of the father be = 2x

20 years ago ,

The age of the son is = x-20

and the age of the father is = 2x-20

( 2x-20 ) = 12 × ( x-20 )

( 2x-20 ) = ( 12x -240 )

2x = 12x - 240 + 20

2x = 12x-220

-10x= -220

-220 ÷ (-10 ) = 22

➡ SO THE PRESENT AGE OF THE SON IS = 22 years.

➡ THE PRESENT AGE OF THE FATHER IS = 2×22 = 44 years

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Answer 2

Step-by-step explanation:

If to find the age of son.

Let the age of son be x.

then the father's age be 2x.

it was 20years ago twice.

so.

acorrding to question.

12x -20 =2(x-20)

12x-2x = 40+20

10x = 60

x = 60/10

x= 6