A father is twice as old as his son and the sum of their ages is 90 years; find their percent ages?
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Let the present age of be "x"
Given father age is twice age of his son = 2x
Sum of their ages=90 (given)
=>x+2x=90
=>3x=90
=>x=90/3
=>x=30
●The present age of son is 30 yrs (x)
●Present age of their father is 2x=2×30=60 yrs
Hope this helps u. . . ✌
Given father age is twice age of his son = 2x
Sum of their ages=90 (given)
=>x+2x=90
=>3x=90
=>x=90/3
=>x=30
●The present age of son is 30 yrs (x)
●Present age of their father is 2x=2×30=60 yrs
Hope this helps u. . . ✌
LalsanbabuKaipeng:
Let x be the son and 2x be the father. sum of their ages (2x +x ) =90. so 3× =90. ×=90 ÷3=30. So his son = 30 years old. Father is twice older than than his son. so he is 2x30 =60 years old.
thanks
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