A father is twice as old as his son,the sum of the ages is 99 years.Find their ages
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Answered by
7
Let the age of son be x.
Age of father = 2x
According to the question,
x+2x = 99
3x = 99
x = 33
Age of son = x = 33 years
Age of father = 2x = 2×33 = 66 years
Answered by
2
Answer:
let son's age be x
and his father's age be 2x
Step-by-step explanation:
(as per question)
x+2x=99
3x=99
x=99/3
x=33
son'age =33
father's age =33×2
=66
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