Question

A father is twice the age of his son and thrice the
age of his daughter. If the son is 10 years older than
the daughter, then age of the father is​

Answer 1

Answer:

Let the age of father be x years, the age of elder son be y years

and the age of younger son be z years.

From the first condition, we have

x=2y ...(i)

From the second condition, we have

x+10=3(z+10)

∴x+10=3z+30

∴x−3z=20 ...(ii)

From the third condition, we have

y−z=15 ...(iii)

Put the value of y from eqn. (i) in (iii) we get

x−2z=30 ...(iv)

Solving (ii) and (iv), we get

x=50

∴ the age of the father is 50 years.

$\bf{ }$

Answer 2

Step-by-step explanation:

Let Son's age = S

Father's age = F

then, F−10=3(S−10)

F=3S−20

and, F+10=2(S+10)

F=2S+10

Thus, 3S−20=2S+10

S=30 years

Hence, F=70 years

Hence required ratio = 7:3...

hope it helps u.......