a father runs after his son who is 1000 m ahead. the father runs at the speed of 1 km every 8 minutes and the son runs at the speed of 1 km every 12 minutes. How much distance has the son covered at the point where the father overtakes the son?
a) 2500 m
b) 3000 m
c) 2000 m
d) 1500 m
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Answer:
it is 2000m
Step-by-step explanation:
Time taken is same for father and son
time taken by son =x/5km/hr
time taken by father =(1000+x)/7.5
Since , time taken is same x/5=(1000+x)/7.5 or x =2000
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X=2000m
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