A father's age is 3 times the sum of ages of his 2 sons. Five years later he will be twice the sum of ages of his 2 sons. Find the present age of the father.
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Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
- Suppose that the sum of sons' age = x
- so father's age = 3×x =3x
- so father's age five year later =3x - 5
- the sum of age of sons five year later =x-10
- so father's age five years later = 2×(x-10) =2x - 20
- therefore 3x - 5 = 2x - 20
3x -2x = -20 + 5
x = - 15
- Since age will be positive therefore x = 15
- So father's present age = 3x = 3 × 15 = 45
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