Question

A father's age is 3 times the sum of ages of his two sons. Five yeara later he will be twice the sum of ages of his two sons. Find the present age of the father.






Kindly solve this question of 'Linear Equations in One Variable'.​

Answer 1

Let the age of father be x years and sum of the ages of his children by y years.

After 5 years,

Father's age = (x + 5) years

Sum of ages of his children = (y + 10) years

From the given information, we have:

x = 3y ...(1)

and x + 5 = 2(y + 10)

x - 2y = 15 ...(2)

From (1) and (2), we have,

3y - 2y = 15  y = 15

x = 3y = 45

Father's age = 45 years

Answer 2

Answer:

Son's age = 5

And fathers age = 3*5 = 15

Step-by-step explanation:

Let the current age of son be x

So the current age of Father = 3x

Five years later=)

Son's age = x + 5

Father's age = 3x + 5

A/Q

2(x+5) = 3x + 5

= 2x + 10 = 3x + 5

= 2x - 3x = 5 - 10

= -x = -5

= x = 5

Therefore son's age = 5

And fathers age = 3x

= 3*5= 15