A father's age is equal to the sum of the ages of his 5 children. In 15 years his age will be only half of the sum of their ages. How old is the father?
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Let us consider the age of the father x and the sum of ages of the 5 children as y.
At present,
x=y−−−−(i)
After 15 years,
Father’s age = x + 15
Sum of children’s ages = y + 5*15 (Because in the course of 15 years, each child will grow by 15 years)
x+15=1/2(y+5∗15)−−−−(ii)
Solving (i) and (ii), we get by substituting the value of x from (i) in (ii)
y+15=1/2(y+5∗15)
=>2y+30=y+75
=> y=45
which implies, x = 45
The age of the father is 45 years
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