Question

A father's age is four times his son's present age. After 18 years the
father's age will be twice his son's age. The father's and son's
present ages are respectively:
(A) 40, 10 yrs
(B) 32, 8 yrs
(C) 44, 11 yrs
(D) 36, 9 yrs​

Answer 1

Hey frnd

if this solution really helps you

than

plz mark me as brainlist

and follow me plz !!!!!

Answer 2

Given,

A father's age is four times his son's present age.

After 18 years the father's age will be twice his son's age.

To Find,

The present age of the father's and son's .

Solution,

Suppose the son's present age is x years.

So as given father's current age will be 4x.

After 18 years son's age will be x+18 years and the father's age will be 4x+18.

But as per the given condition,

then,

4x+18=2×(x+18)

⇒4x+18=2x+36.

⇒2x=18.

⇒x=9.

So son's current age is 9 years and fathers current age is 9×4=36 years.

Hence, The father's and son's present ages are respectively (D) 36, 9 yrs​.