Question

a father's age is three times the sum of Ages of his two sons five years later he will be twice the sum of Ages of his two sons find the present age of father... Plz fast tomorrow is my exam

Answer 1

Let One Son Age=x years

Let Age of Other Son=Y years

Sum of their ages=(x+Y) years

Father age is 3 times(x+Y)

Father Age=3(x+Y)

5 years Later

Age of One Son will be =(x+5) years

Other son Age will be=(Y+5) years

Father Age will be =3(x+Y)+5

Father will be also Now 2 times The age of sons After Five Years

Sum of Ages after 5 years=(x+5+Y+5)

=(x+Y+10) years

A/Q

3(x+Y)+5=2(x+Y+10)

3x+3y+5=2x+2y+20

3x+3y-2x-2y=20-5

x+Y=15

sum of ages of Son=x+Y=15 years

Father is 3 times There sum

3×15=45

$\boxed{\mathtt{\huge{Father=45\:years}}}$