Question

A father's age is three times the sum of the ages of his two children. After 5 years his
age will be two times the sum of their ages. Find the present age of the father.
no cho takes a fixed charge for the first two​

Answer 1

Answer:

Step-by-step explanation:

let the age of two children be x and y.

father's present age is 3(x+y).

age of children after 5 years= x+5+y+5

                                       = x+y+10

age of the father after 5 years= 2(x+y+10) or 3(x+y)+5

                       2x+2y+20 = 3x+3y+5

                       2x-3x + 2y-3y= -20+5

                                   -(x+y) = -15

                                    x+y = 15

                               3(x+y) = 3(15)

                                                 =45

               therefore, present age of father is 45.

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Answer 2

Answer:

ok! ok! ok! ok! ok! ok!!!!