a faulty thermometer reads 5C in melting ice and 99C in steam. Find the correct temperature in F when this faulty thermometer reads 52C
Answers
Answered by
80
(T-LFP)÷(UFP-LFP) = (F -32)÷180
T= given temp in scale
LFP- lower fix point/ice point of given scale
UFP- Upper fix point/steam point of given scale
F- temp in farenh. scale
(52-5)÷(99-5)=(F-32)÷180
on solving F = 112°F...
Hope it helped you...if did then follow nd rate the ans.
T= given temp in scale
LFP- lower fix point/ice point of given scale
UFP- Upper fix point/steam point of given scale
F- temp in farenh. scale
(52-5)÷(99-5)=(F-32)÷180
on solving F = 112°F...
Hope it helped you...if did then follow nd rate the ans.
gummaliki1927:
i think answer is 122F but thanks for the procedure
Answered by
37
As per the question, the temperature when C=52° C shown by thermometer
(C-0)/100 = (52-5) / 99-5 gives C=50° C which is the actual temperature.
Hence, the correct temperature in Fahrenheit is 50*1.8 +32 = 122° F
(C-0)/100 = (52-5) / 99-5 gives C=50° C which is the actual temperature.
Hence, the correct temperature in Fahrenheit is 50*1.8 +32 = 122° F
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