Question

A ferris wheel has a diameter 212 feet. How far will a passenger travel in one revolution of the wheel?

Answer 1

Answer:

655.018 feet

Step-by-step explanation:

Diameter =212 feet

Radius =106 feet

Perimeter of circle =2*3.14*106

=655.08feet

Answer 2

Answer:

⋆ DIAGRAM :

$\setlength{\unitlength}{1mm}\begin{picture}(50,55)\thicklines\qbezier(25.000,10.000)(33.284,10.000)(39.142,15.858)\qbezier(39.142,15.858)(45.000,21.716)(45.000,30.000)\qbezier(45.000,30.000)(45.000,38.284)(39.142,44.142)\qbezier(39.142,44.142)(33.284,50.000)(25.000,50.000)\qbezier(25.000,50.000)(16.716,50.000)(10.858,44.142)\qbezier(10.858,44.142)( 5.000,38.284)( 5.000,30.000)\qbezier( 5.000,30.000)( 5.000,21.716)(10.858,15.858)\qbezier(10.858,15.858)(16.716,10.000)(25.000,10.000)\put(5,30){\line(5,0){40}}\put(25,30){\circle*{1}}\put(20,25){\sf\large{212 feet}}\end{picture}$

$\rule{160}{1}$

• Distance travelled by wheel in one revolution will be equal to Perimeter of Wheel.
• Diameter of Wheel = 212 feet

$\underline{\bigstar\:\:\textsf{According to the Question :}}$

$:\implies\sf Perimeter_{wheel}=2\pi Radius\\\\\\:\implies\sf Perimeter_{wheel}=\pi \times Diameter\\\\\\:\implies\sf Perimeter_{wheel}=\dfrac{22}{7} \times 212\:feet\\\\\\:\implies\sf Perimeter_{wheel}=22 \times 30.28\:feet\\\\\\:\implies\underline{\boxed{\textsf{\textbf{Perimeter _{\textbf{wheel}} = 666.16 feet}}}}$

⠀

$\therefore\:\underline{\textsf{Passenger will go \textbf{666.16 feet} in one revolution}}.$