A field 120m long and 80m wide has two cross roads in centre. Each road 5m wide. The sum of area of cross roads is:
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Step-by-step explanation:
Solution :
AB+BC+CD=70cm
2AB=65
AB=65/2
Area of path= AB*5+CD*5+45*5
=(652)⋅5+(652)⋅5+225
=550m2
Total cost= 550*105
=57,750Rs.
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