Question

A field in the shape of a quadrilateral ABCD in which side AB = 18 m side AD = 24 m side BC = 40 m DC = 50 m and angle A = 90° . Find the area of the field​

Answer 1

The quadrilateral ABCD is divided into two triangles.  ABD and BCD.

ABD is a right angle triangle.

     Area = 1/2 AB * AD as angle A is 90, AB is the altitude and AD is the base.

             = 1/2 * 18 * 24 = 216 cm^2

     BC^2 = AB^2 + AD^2    =>  BC = 30 cm

BCD triangle

     s = semi perimeter = 60 cm

 area = sqroot(60 * 30 * 20 * 10 ) = 600 cm^2

total area = 816 cm^2