Question

baichungs father is 26 years younger than baichungs grandfather and 29 years older than baichung. the sum of their ages is 135 what is the age of each one of them​

Answer 1

Step-by-step explanation:

father's age=x=46

grandpa's age=(x+26)=46+26=72

baichungs age=(x-29)=46-29=17

x+x+26+x-29=135

x=46

Answer 2

According to the given question, the sum of the ages of these 3 people is 135 years

Therefore , x+x-29+X+26 = 135

3x-3 = 135

On transposing 3 to R.H.S , we obtain

3x = 135+3

3x = 138

On dividing both sides by 3 , we obtain

$\frac{3x}{3} = \: \frac{138}{3}$

x = 46

Baichung's father's age = x years = 46 years .

Baichung's age = (x-29) years = (46-29) years = 17 years

Baichung's grandfather's age = (X+26) years = (46+26) years = 72 years