a field in the shape of a quadrilateral has its diagonal as 28 m and the perpendicular distances of other two vertices from the diagonal are 32.5 and 22 m . find the area of the field.
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Answer:
two triangle are formed on base as diagonal
and height given
so area of quad. = 1/2*28*32.5 +1/2*28*22
= 455+308=763
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