a field in the shape of trapezium.one of its parallel sides is twice the other parallel side and distance between them is 100 m.if area is 10500 m find the hight of trapezium
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Let one parallel be x and other be 2x.
Ar. of trap.= 1/2×3x×100=10500
150x=10500
x=10500/150
x=7
Therefore,
One parallel= 7m
Second parallel= 14m
Ar. of trap.= 1/2×3x×100=10500
150x=10500
x=10500/150
x=7
Therefore,
One parallel= 7m
Second parallel= 14m
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