A field is 70 m long and 40 m wide. In one corner of the field, a pit which is 10 m long, 8 m
broad and 6 m deep has been dug. Soil taken out of it is evenly spread over the remaining
part of the field. Find the rise in the level of the field.
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Answer:
Area of the field on which earth taken out is to be spread
= 70 X 40 m2 - 10 X 8 m2
= 2800 m2 - 80 m2 = 2720 m2
Volume of the earth dug out = 10 X 8 X 5 m3 = 400 m3
Rise in level of the field = Volume of the earth dugout/Area on which earth taken out is to be spread
= 400/2720 = 0.147 m = 14.7 cm
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