Math, asked by harshdeepyadav612, 1 month ago


A field is 70 m long and 40 m wide. In one corner of the field, a pit which is 10 m long, 8 m
broad and 6 m deep has been dug. Soil taken out of it is evenly spread over the remaining
part of the field. Find the rise in the level of the field.

Answers

Answered by raj1564
2

Answer:

Area of the field on which earth taken out is to be spread

= 70 X 40 m2 - 10 X 8 m2

= 2800 m2 - 80 m2 = 2720 m2

Volume of the earth dug out = 10 X 8 X 5 m3 = 400 m3

Rise in level of the field = Volume of the earth dugout/Area on which earth taken out is to be spread

= 400/2720 = 0.147 m = 14.7 cm

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