a field is 80 metre long 50 M broad in a one corner of the field with which is a 10 metre long 7.5 M broad and 8 M deep has been dug out the earth taken off its evenly spread over the remaining part of the field find the Rise and the level of the field
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Solution:-
Length of field = 80 m
Breadth of field = 50 m
Length of pit = 10 m
Breadth of pit = 7.5 m
Height of pit = 8 m
Volume of earth taken out = volume of pit
= L*B*H
= 10*7.5*8
= 600 cu m
Area of rectangular field = 80*50
= 4000 sq m
Area of the base of pit = 10*7.5
= 75 sq m
Area of remaining portion of rectangular field = Area of rectangular field - Area of the base of pit
= 4000 - 75
= 3925 sq m
Now rise in the level of remaining part of the field = 600/3925
= 0.1528 m or 15.28 cm
So, rise in the remaining part of the field = 15.28 cm
Answer.
Length of field = 80 m
Breadth of field = 50 m
Length of pit = 10 m
Breadth of pit = 7.5 m
Height of pit = 8 m
Volume of earth taken out = volume of pit
= L*B*H
= 10*7.5*8
= 600 cu m
Area of rectangular field = 80*50
= 4000 sq m
Area of the base of pit = 10*7.5
= 75 sq m
Area of remaining portion of rectangular field = Area of rectangular field - Area of the base of pit
= 4000 - 75
= 3925 sq m
Now rise in the level of remaining part of the field = 600/3925
= 0.1528 m or 15.28 cm
So, rise in the remaining part of the field = 15.28 cm
Answer.
dolly8205:
can you explain me
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Answer:
15.3
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