Question

in the figure ABCD is a quadrilateral such that AC= 22 cm BM=3 cm DN= 3 cm . find the area of the quadrilateral ABCD

Answer 1

hola there

The figure is shows a quadrilateral ABCD in which BM⊥AC  and  DN⊥AC 
Here AC = 22 cm; BM = 3 cm and DN = 3 cm
Now; area of triangle ACD = 12×AC×DN = 12×22×3 = 33 cm2
Also, area of triangle ABC = 12×AC×BM = 12×22×3 = 33 cm2
So, area of quadrilateral ABCD = area of triangle ACD + area of triangle ABC = 33 cm2 + 33 cm2 = 66 cm2

Answer 2

Answer:

66cm^2 is the answer

Step-by-step explanation:

To find the area of quadrilateral ABCD, first we have to find the area of ΔABC, and ΔADC Area of ΔABC = ½ × Base × Height

= ½ × 22 × 3

= 1 × 11 × 3

= 33 cm2

Area of ΔADC = ½ × Base × Height

= ½ × 22 × 3

= 1 × 11 × 3

= 33 cm2

Then,

Area of quadrilateral ABCD = Area of ΔABC + Area of ΔADC

= 33 + 33

= 66 cm2