Math, asked by rahimkataria, 1 year ago

A field is in the form of a rectangle of length 18m and width 15m. a pit 7.5m long, 6m broad and 0.8m deep is dug in the corner of the field and the earth taken out is spread over the remaining area of the field find the extent to which the level of the field has been raised.

Answers

Answered by Aditya25AT
19

See the attachment Its written in the picture which is a attachment    

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rahimkataria: of thanks bro or sis
Answered by Anonymous
42

Given:-

  • Length of the Rectangle = 18m

  • Width of the Rectangle = 15m

  • Length of Pit = 7.5m

  • Breadth of Pit = 6m

  • Height of Pit = 0.8m

To Find:-

  • The Height of the field raised?.

Formulae used:-

  • Area of Rectangle = Length × Breadth

  • Volume of Cuboid = L × B × H

Now,

Area of whole field = 18 × 15

→ Area of whole field = 270m²

Now,

Atq.

  • A pit is dug in the corner of the Field.

So,

→ Area of Dug = 7.5 × 6 = 45m²

Therefore,

→ Remaining Field = Area of whole field - Area of Dug

→ Remaining Field = 270 - 45 = 225m²

Hence,

  • The earth after being taken out from pit is spreaded in this area only.

So,

→ Volume of Pit = Volume of the Field

→ 7.5 × 6 × 0.8 = 225 × h

→ 36 = 225h

→ h = 36/225

→ h = 0.16m

→ h = 16cm.

Hence, The extent to which level of field has been raised is 16cm

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