Question

A field is in the form of a rhombus whose each  side is 64m and altitude is 16m. Find the side of a square field whose area is equal to that of the rhombus. Find the difference in their perimeters.
Answer with step by step explaination.

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Answer 1

Answer:

Area of rhombus = b × h

= 64 × 16

= 1024 m²

Area of square = 1024 m²

side². = 1024

side. =

$\sqrt{1024}$

side of square = 32 m

Perimeter of rhombus = 4 × side

= 4 × 32 = 128 m

Perimeter of square. = 4 × side

= 4 × 32 = 128 m

Answer 2

Answer:

Area of rhombus = b × h

= 64 × 16

= 1024 m²

Area of square = 1024 m²

side². = 1024

side. =

\sqrt{1024}

1024

side of square = 32 m

Perimeter of rhombus = 4 × side

= 4 × 32 = 128 m

Perimeter of square. = 4 × side

= 4 × 32 = 128 m