Question

a field is in the form of trapezium whose parallel sides are 45.2m and 22.8 M long and the distance between them is 12m find the cost of levelling it at 3 rupees per square metre

Answer 1

Parallel sides = 45.2 and 22.8
height =12
area of trapezium =1÷2×(sum of parallel lines )height
=1÷2×68×12
=68×6
=408
cost of levelling = 3 per m square
total cost =408×3=rupees1224



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Answer 2

find area using equation =  1/2*sum of parallel sides*height

                                          =1/2(45.2+22.8)*12

total cost=    area of  trapezium* costper square metre

              =     1/2(45.2+22.8)*12    *    rs 3

              =     rs 1224