what is √(sina+cosa)/(sina-cos) if sina+cosa=3
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Ans is 1/(2sina-3)
because after rationalising the equation
we get √(sin²a+cos²)/(sina-cosa)²
=1/sina-cosa
=1/sina-3+sina
=1/2sina-3
because after rationalising the equation
we get √(sin²a+cos²)/(sina-cosa)²
=1/sina-cosa
=1/sina-3+sina
=1/2sina-3
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