A field is in the shape of quadrilateral ABCD in which side AB = 18 m, side AD = 24 m, side BC = 40 m, DC = 50 m and angle A = 90 degree . Find the area of the field.
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in ABD Angle A is 90° so area is found by 1/2 base *height and in angle C will also be 90° so find it also by 1/2base *height
at last add both the 's area
hence you got the final answer
at last add both the 's area
hence you got the final answer
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