a field is in the shape of trapezium whose parallel sides are 35 and 15 the non parallel sides are 16 and 18 find the area of the field
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Construction:
⇒Draw BE∥AD such that D−E−C
⇒Draw BM⊥DC such that D−E−M−C
□ABED is parallelogram,
⇒AD=BE=13 m
⇒AB=DE=10 m
⇒BC=14 m
⇒DC=DE+EC ....(∵D−E−C)
∴EC=25−10
∴EC=15 m
⇒In ΔBEC
⇒2S=13+14+15
⇒S=21 m
⇒Area of △BEC
____________
⇒A= root of √s(s−a)(s−b)(s−c)
__________________
= √21(21−13)(21−14)(21−15)
_________
= √21×8×7×6
=84 m ^2
⇒Area of ΔBCE= 1/2×BM×EC
⇒BM= (84×2)/15=11.2 cm
⇒Area of □ABED=11.2×10=112 m ^2
⇒Area of the field □ABCD
=84+112 m ^2
=196 m ^2
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