Math, asked by gpbhuyargmailcom, 1 year ago

A field is in the shape of trapezium whose parallel sides are 35m and 10m The non parallel sides are 14m and 13m. Find area

Answers

Answered by Anonymous
19


Let ABCD is a trapezium such that AB = 35m, BC = 13 m, CD = 10 m and DA = 14 m 
Draw a line DE parallel to the side BC =13 m therefore DE = 13 m 
AE+ED+DA = 15+13+14 = 42 
2s= 42 or s = 21 
Area of triangle DAE using Hero's formula = sqrt{ 21(21-15)(21-14)(21-13)} = 84 m^2............(i) 
DF is a perpendicular from D on AE= h 
Area of triangle = (1/2)(15)(h)............................... 
from (i) and (ii) 
(15/2)*h = 84 
h = (84*2)/15 = 11.2 m...................................(iii... 
Area of parallelogram = 10*11.2 = 112 m^2...........................(iv) 
Therefore area of trapezium = Area of triangle+ Area of parallelogram 
= 84 +112 = 196 m^2..............................Ans

Answered by PaarthJn
7

Answer:

114.63

Step-by-step explanation:

divide the trapezium into a parallelogram and a triangle. find their respective areas and then add them up to find the area of the trapezium.You will get 114.63 square meter as the answer

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