A field is in the shape of trapezium whose parallel sides are 35m and 10m The non parallel sides are 14m and 13m. Find area
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19
Let ABCD is a trapezium such that AB = 35m, BC = 13 m, CD = 10 m and DA = 14 m
Draw a line DE parallel to the side BC =13 m therefore DE = 13 m
AE+ED+DA = 15+13+14 = 42
2s= 42 or s = 21
Area of triangle DAE using Hero's formula = sqrt{ 21(21-15)(21-14)(21-13)} = 84 m^2............(i)
DF is a perpendicular from D on AE= h
Area of triangle = (1/2)(15)(h)...............................
from (i) and (ii)
(15/2)*h = 84
h = (84*2)/15 = 11.2 m...................................(iii...
Area of parallelogram = 10*11.2 = 112 m^2...........................(iv)
Therefore area of trapezium = Area of triangle+ Area of parallelogram
= 84 +112 = 196 m^2..............................Ans
Answered by
7
Answer:
114.63
Step-by-step explanation:
divide the trapezium into a parallelogram and a triangle. find their respective areas and then add them up to find the area of the trapezium.You will get 114.63 square meter as the answer
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