Plzzz answer this question plzzz
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x2+9-6x+y2+36-12y=x2+9+6x+y2+16-8y
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(x-3)^2+(y-6)^2=(x+3)^2+(y-4)^2
-12x-4y+20=0
3x+y-5=0
-12x-4y+20=0
3x+y-5=0
Answered by
0
√(3-x)^2+(6-y)^2=√(x-(-3))^2+(y-4)^2
9+x^2-6x+36+y^2-12y=x^2+9+6x+y^2+16-8y
36-12y=16-8y+12x
12x+4y=20
3x+y=5
9+x^2-6x+36+y^2-12y=x^2+9+6x+y^2+16-8y
36-12y=16-8y+12x
12x+4y=20
3x+y=5
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