Question

a field mesures90 m by 60 m , there is a concrete path 3 m wide all round its perimeter , find the perimeter of the outer boundary and total rea enclose by the concrete path

Answer 1

Answer:

Perimeter of outer boundary is 24m

total area enclosed by concrete path is 6636m

Step-by-step explanation:

• in this case we are dealing with a rectangular area.

part1

perimeter of outer boundary is given by:

perimeter of outer boundary is given by: > the difference in perimeter between the outer rectangular area and the inner rectangular area,i.e:

perimeter of outer boundary is given by: > the difference in perimeter between the outer rectangular area and the inner rectangular area,i.e: (outer area - inner area)

perimeter of a rectangle is given by:

perimeter of a rectangle is given by: p = 2(L + W)

therefore;

perimeter of Outer area:

we first add 3+3 = 6 to our current length and width to get the new measurements for the outer rectangular area i.e:

L = 90+6 = 96m, W = 60+6 = 66

Hence,

P = 2(96m + 66m) = 324m

perimeter of Inner area:

we have;

L = 90m

W = 60m

Hence,

p = 2(90m + 60m) = 300m

Perimeter of outer boundary is given by:

√ (P - p)

324m - 300m = 24m

part2

area enclosed by the concrete is:

A = L × W

L = 96m

W = 66m

therefore, A = (96×66)m = 6336m

total area enclosed by concrete path is 6636m