a fighter aeroplane flying in the sky dives with a speed of 360 km/hr in a vertical circle of radius 200 m. weight of the pilot sitting in it is 75 kg. what will be the value of force with which the pilot presses his seat when the aeroplane is at highest position (g = 10 m/s2)
Answers
Answered by
30
convert speed into m/s
at the top of the circle Fc = T+mg
mv2/r = T + mg
T = mv2 /r - mg
= 75*1002 / 200 -75*10
T= 3000N
Only this much knowledge I have friend I solved problems of motion in vertical circle which involved string and stone. this is new to me but I am sure that this is the correct ans, I don't know what to write in place of T , if you know plz tell me also.
at the top of the circle Fc = T+mg
mv2/r = T + mg
T = mv2 /r - mg
= 75*1002 / 200 -75*10
T= 3000N
Only this much knowledge I have friend I solved problems of motion in vertical circle which involved string and stone. this is new to me but I am sure that this is the correct ans, I don't know what to write in place of T , if you know plz tell me also.
lakhabhawan:
copied from meritnation
Answered by
22
Hey mate ^_^
At the top point:
The pilot will experience mg downwards,
Normal force also downwards.
These both together will add up to give the require centrifugal acceleration
= mv^2/rN + mg
= mv^2/rN
=mv^2/r−mg
= mv^2/r−mg
= 75(1002 /200 − 10)
= 3000 N
#Be Brainly❤️
At the top point:
The pilot will experience mg downwards,
Normal force also downwards.
These both together will add up to give the require centrifugal acceleration
= mv^2/rN + mg
= mv^2/rN
=mv^2/r−mg
= mv^2/r−mg
= 75(1002 /200 − 10)
= 3000 N
#Be Brainly❤️
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